The average veloctiy of an ideal gas mol...

The average veloctiy of an ideal gas molecule at `27^(@)C` is `0.3 m s^(-1)`. The average velocity at `927^(@)C` will be

A

`0.6 m s^(-1)`

B

`0.3 ms^(-1)`

C

`0.9 ms^(-1)`

D

`3 ms^(-1)`

Verified by Experts

The correct Answer is:

A

`(bar(v) (T_(1)K))/(bar(v) (T_(2)K)) = sqrt((T_(1))/(T_(2)))`
`(0.3)/(bar(v) (T_(2)K)) = sqrt((300)/(1200))`
`bar(v) (T_(2)K) = 0.6 ms^(-1)`

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