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50 ml of gas A diffuses through a membra...

50 ml of gas A diffuses through a membrane in the same time as for the diffusion of 40 ml of a gas B under identical pressure-temperature conditions. If the molecular weight of A is 64 then, that of B would be

A

100

B

250

C

200

D

80

Text Solution

Verified by Experts

The correct Answer is:
A
`(V_(1))/(V_(2)) = sqrt((M_(2))/(M_(1)))`
`(50)/(40) = sqrt((M_(2))/(64))`
or `sqrt(M_(2)) = (5)/(4) xx 8 = 10`
`M_(2) = 100`
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