Home
Class 11
CHEMISTRY
The average kinetic energy of an ideal g...

The average kinetic energy of an ideal gas per molecule in SI unit at `25^(@)C` will be:

A

`6.17 xx 10^(-21) kJ`

B

`6.17 xx 10^(-21)J`

C

`6.17 xx 10^(-20) J`

D

`7.16 xx 10^(-20)J`

Text Solution

Verified by Experts

The correct Answer is:
B
`K.E. = (3)/(2) KT = (3)/(2) (RT)/(N)`
`= (3)/(2) xx (8.314 KJ^(-1) mol^(-1) xx 298 K)/(6.023 xx 10^(23) mol^(-1))`
`= 6.17 xx 10^(-21) J`
Promotional Banner

Similar Questions

Explore conceptually related problems

The average kinetic energy of an ideal gas per molecule in SI units at 25^(@)C will be

The average kinetic energy of an ideal gas per molecule in SI units at 25^(@)C will be

The average kinetic energy of a gas molecule is

Kinetic energy per mole of an ideal gas is :

The translational kinetic energy of an ideal gas depends only its

The average kinetic energy in Joule of the molecules in 8 grams of CH_(4) at 27^(@)C is

Calculate the average kinetic energy of a hydrogen molecule at 27^@C .

Kinetic energy of one of an ideal gas at 300 K in kJ is

Calculate the average kinetic energy in joules of the molecules in 8.0 g of methane at 27^@C .

The average kinetic energy of one molecule of an ideal gas at 27^@C and 1 atm pressure is [Avogadro number N_A=6.023xx10^(23) ]