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The kinetic enerrgy of 4 mole sof nitrog...

The kinetic enerrgy of 4 mole sof nitrogen gas at `127^(@)C` is `(R=2" cal "mol^(-1)K^(-1))`

A

4400

B

3200

C

4800

D

1524

Text Solution

Verified by Experts

The correct Answer is:
C
K.E. of 1 mole of a gas
`=(3)/(2) RT = (3)/(2) xx 2 cal K^(-1) xx (127 + 273) K`
`= 3 xx 400 cal mol^(-1)`
`= 1200 cal mol^(-1)`
K.E. of 4 moles of gas `= 4 mol xx (1200 cal mol^(-1))`
`=4800 cal`
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