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If u("rms") of a gas is 30R^(1//2)ms^(-1...

If `u_("rms")` of a gas is `30R^(1//2)ms^(-1)` at `27^(@)C` then the molar mass of gas is :

A

1

B

2

C

4

D

0.001

Text Solution

Verified by Experts

The correct Answer is:
D
`V_(rms) = sqrt((3RT)/(M)) " or " (30 R^(1//2))^(2) = (3RT)/(M)`
i.e., `900 R = (3R xx 300)/(M)`
or `M = 1 g mol^(-1) = 0.001 kg mol^(-1)`
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