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A 4:1 molar mixture of He and CH4 is con...

A 4:1 molar mixture of He and `CH_4` is contained in a vessel at 20 bar pressure.Due to a hole in the vessel, the gas mixture leaks out.What is the composition of the mixture effusing out initially ?

A

`8 : 1`

B

`8 : 3`

C

`4 : 1`

D

`1 : 1`

Text Solution

Verified by Experts

The correct Answer is:
A
`(r(He))/(r(CH_(4))) = sqrt((M_(CH_(4)))/(M_(He))) = sqrt((16)/(4)) = 2`
Initital composition of mixture,
`He : CH_(4) :: 4 : 1`
Composition of mixture effusing out ,
`He : CH_(4) :: 4 xx 2 : 1 " or " 8 : 1`
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