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If the ratio of masses of SO(3) and O(2)...

If the ratio of masses of `SO_(3)` and `O_(2)` gases confined in a vessel is 1 : 1 , then the ratio of their partial pressures would be

A

`5 : 2`

B

`2 : 5`

C

`2 : 1`

D

`1 : 2`

Text Solution

Verified by Experts

The correct Answer is:
B
`SO_(3) = O_(2) = 10 g :. N_(SO_(3)) = (w)/(80), n_(O_(2)) = (w)/(32)`
The partial pressures will be in the ratio of their moles
Hence `p_(SO_(3)) : p_(SO_(2)) = (w)/(80) : (w)/(32) = (1)/(80) : (1)/(32) = (1)/(5) : (1)/(2) " or " 2 : 5`
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