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0.5 mol of H(2), SO(2), and CH(4) is kep...

`0.5 mol` of `H_(2)`, `SO_(2)`, and `CH_(4)` is kept in a container. A hole was made in the container. After `3 hours`, the order of partial pressure in the container will be

A

`pSO_(2) gt pH_(2) gt pCH_(4)`

B

`pSO_(2) gt pCH_(4) gt pH_(2)`

C

`pH_(2) gt pSO_(2) gt pCH_(4)`

D

`pH_(2) gt pCH_(4) gt pSO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Rate of effusion of a gas `prop sqrt((1)/("Mol mass"))`
`:.` Rate of effusion of gases is `H_(2) gt CH_(4) gt SO_(2)`
`:.` The partial pressure of gases left in the container is `p_(SO_(2)) gt p_(CH_(4)) gt p_(H_(2))`
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