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If 1 ml of water contains 20 drops. Then...

If 1 ml of water contains 20 drops. Then no. of molecules in a drop of water is

A

`6.023 xx 10^(23)` molecules

B

`1.376 xx 10^(26)` molecules

C

`1.667 xx 10^(21)` molecules

D

`4.346 xx 10^(20)` molecules

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of molecules in a drop of water, we can follow these steps: ### Step 1: Determine the mass of water in one drop. Given that 1 ml of water contains 20 drops, we can find the mass of one drop. - Since 1 ml of water has a mass of 1 gram, we can calculate the mass of one drop as follows: \[ \text{Mass of one drop} = \frac{1 \text{ gram}}{20 \text{ drops}} = 0.05 \text{ grams} \] ### Step 2: Calculate the number of moles in one drop. To find the number of moles, we use the formula: \[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] The molar mass of water (H₂O) is approximately 18 g/mol. - Therefore, the number of moles in one drop of water is: \[ \text{Number of moles} = \frac{0.05 \text{ grams}}{18 \text{ g/mol}} \approx 0.00278 \text{ moles} \] ### Step 3: Calculate the number of molecules in one drop. To find the number of molecules, we use Avogadro's number, which is approximately \(6.022 \times 10^{23}\) molecules/mol. - The number of molecules in one drop can be calculated as follows: \[ \text{Number of molecules} = \text{Number of moles} \times \text{Avogadro's number} \] \[ \text{Number of molecules} = 0.00278 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mol} \approx 1.673 \times 10^{21} \text{ molecules} \] ### Final Answer: The number of molecules in a drop of water is approximately \(1.673 \times 10^{21}\) molecules. ---

To find the number of molecules in a drop of water, we can follow these steps: ### Step 1: Determine the mass of water in one drop. Given that 1 ml of water contains 20 drops, we can find the mass of one drop. - Since 1 ml of water has a mass of 1 gram, we can calculate the mass of one drop as follows: \[ \text{Mass of one drop} = \frac{1 \text{ gram}}{20 \text{ drops}} = 0.05 \text{ grams} ...
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