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The pressure exerted by 6.0 g of methane...

The pressure exerted by 6.0 g of methane gas in a `0.03 m^(3)` vessel at `129.^(@)C` is
(Atomic masses : C = 12.01, H = 1.01 and `R=8.314 JK^(-1) mol^(-1)`)

A

215216 Pa

B

13405 Pa

C

41648 Pa

D

31684 Pa

Text Solution

Verified by Experts

The correct Answer is:
C
Mass of `CH_(4), W = 6g`
Molecular mass of `CH_(4) = 12.01 + 4 xx 1.01 = 16.05`
`V = 0.03 m^(3), T = 129 + 273 = 402 K`
`PV = nRT = (W)/(M) RT`
`:. P = (W)/(m) xx (RT)/(V) = (6)/(16.05) xx 8.314 xx 402`
`= 41647.7 Pa = 41648 Pa`
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