Home
Class 11
CHEMISTRY
At identical temperature and pressure, t...

At identical temperature and pressure, the rate of diffusion of hydrogen gas is `3sqrt(3)` times that of a hydrocarbon having molecular formula `C_(n)H_(2n-2)`. What is the value of n ?

A

1

B

4

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
B
`(r_(1))/(r_(2)) = sqrt((M_(2))/(M_(1))) , (r_(1))/(r_("hydrogen")) = 3 sqrt3 : M_(1) = 2`
`:. 3 sqrt3 = sqrt((M_(2))/(2)) " or " (M_(2))/(2) = 9 xx 3 = 27`
`:. M_(2) = 54`
Now `12 xx n + 2n - 2 = 56`
`14 n = 56 " or " n = 4`
Promotional Banner

Similar Questions

Explore conceptually related problems

At identical temperature and pressure the rate of diffusion of hydrogen gas is 3sqrt3 times that of a hydrocarbon having molecular formula C_(n)H_(2n-n) What is the value of n ? .

At identical temperature and pressure the rate of diffusion of hydrogen gas is 3sqrt3 times that of a hydrocarbon having molecular formula C_(n)H_(2n-n) What is the value of n ? .

Hydrocarbons having the general formula C_nH_(2n -2) are called___.

The compound having the molecular formula C_(3)H_(9)N can represent

Identify the hydrocarbon having molecular formula C_(5)H_(6) which gives white ppt with ammonical AgNO_(3) ?

The rate of diffusion of a gas X is sqrt(2) times that of Y. If the molecular mass X is 16, what is the molecular mass of gas y?

C_(n)H_(2n)O_(2) is the general formula of

Molecular formula C_3H_9N represents :

Under identical condition of temperature and pressure, 1 litre of CH_(4) weighted 1.2 gram while 2 litre of another gaseous hydrocarbon, C_(n) H_(2n-2) weighted 8.1 gram. What is the value of n ?

At what temperature will the rate of diffusion of N_(2) be 1.6 times the rate of diffusion of SO_(2) at 27°C?