Home
Class 11
CHEMISTRY
Reducing the pressure from 1.0 to 0.5 at...

Reducing the pressure from 1.0 to 0.5 atm would change the number of molecules in one mole of ammonia to

A

75% of initial value

B

50% of initial value

C

25% of initial value

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question "Reducing the pressure from 1.0 to 0.5 atm would change the number of molecules in one mole of ammonia to," we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Moles**: - One mole of any substance contains a fixed number of molecules, known as Avogadro's number, which is approximately \(6.02 \times 10^{23}\) molecules. 2. **Identify the Given Information**: - We have 1 mole of ammonia (NH₃). - The pressure is being reduced from 1.0 atm to 0.5 atm. 3. **Apply the Ideal Gas Law**: - The ideal gas law states that for a given amount of gas at constant temperature, the number of moles (n) is related to pressure (P) and volume (V) by the equation: \[ PV = nRT \] - Here, R is the ideal gas constant and T is the temperature in Kelvin. However, since we are dealing with a fixed amount of gas (1 mole), the number of molecules will remain constant regardless of changes in pressure or volume. 4. **Conclusion**: - Since we have 1 mole of ammonia, it will always contain \(6.02 \times 10^{23}\) molecules, irrespective of the changes in pressure from 1.0 atm to 0.5 atm. Therefore, the number of molecules does not change. 5. **Final Answer**: - The number of molecules in one mole of ammonia remains \(6.02 \times 10^{23}\) molecules.

To solve the question "Reducing the pressure from 1.0 to 0.5 atm would change the number of molecules in one mole of ammonia to," we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Moles**: - One mole of any substance contains a fixed number of molecules, known as Avogadro's number, which is approximately \(6.02 \times 10^{23}\) molecules. 2. **Identify the Given Information**: ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the number of molecules present in 0.5mole of Carbon Dioxide?

The compression factor (compressibility factor) for 1 mol of a van der Waals gas at 0^(@)C and 100 atm pressure is found to be 0.5 . Assuming that the volume of a gas molecule is neligible, calculate the van der Waals constant a .

The compression factor (compressibility factor) for 1 mol of a van der Waals gas at 0^(@)C and 100 atm pressure is found to be 0.5 . Assuming that the volume of a gas molecule is neligible, calculate the van der Waals constant a .

A flask containing 12 g of a gas relative molecular mass 120 at a pressure of 100 atm was evacuated by means of a pump until the pressure was 0.01 atm . Which of the following in the best estimate of the number of molecules left in the flask (N_(0)=6xx10^(23)mol^(-1)) ?

What is the compressibility factor (Z) for 0.02 mole of a van der Waals's gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible. Given : RT=20 L atm mol^(-1) and a=1000 atm L^(2) mol^(-2)

A sample of helium gas is at a temperature of 300 K and a pressure of 0.5 atm . What is the average kinetic energy of a molecule of a gas ?

At 35^(@)C the vapour pressure of pure chloroform is 0.359 at atm and that of pure acetone is 0.453 atm. A solution containing 1 mole of chloroform and 4 mole of acetone has a vapour pressure of (in atm)

If the number of molecules of SO_(2) (atomic weight=64) effusing through an orifice of unit area of cross-section in unit time at 0^(@)C and 1 atm pressure in n. the number of He molecules (atomic weight=4) effusin under similar conditions at 273^(@)C and 0.25 atm is:

One litre of oxygen at a pressure of 1 atm and two litres of nitrogen at a pressure of 0.5 atm are introduced into a vessel of volume 1 litre. If there is no change in temperature, the final pressure of the mixture of gas (in atm) is

5 g of He at 27^(@)C is subjected to a pressure change from 0.5 atm to 2 atm . The initial volume of the gas is 10 dm^(3) . Calculate the change in volume of the gas.