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4 g Argon in a bulb at temperature TK ha...

4 g Argon in a bulb at temperature TK had a pressure of P atm. When the bulb was placed in a hotter bath at a temperature `50^@C` more than the first one, 0.8g of gas had to be removed to get the original pressure. Temperature (T) will be

A

510 K

B

200 K

C

100 K

D

73 K

Text Solution

Verified by Experts

The correct Answer is:
B
`PV = (4)/(M) RT`.....(Case I)
`PV = (3.2)/(M) R (T + 50)`.....(Case II)
`(4)/(3.2) xx (T)/(T + 50) = 1`
`4T = 3.2 T + 160`
`T = (160)/(8.0) = 200 K`
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