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Volume occupied for a cubic close packed...

Volume occupied for a cubic close packed lattice of sphere is

A

`60%`

B

`52.4%`

C

`68%`

D

`74%`

Text Solution

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The correct Answer is:
To find the volume occupied for a cubic close packed (CCP) lattice of spheres, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Structure**: - In a cubic close packed (CCP) lattice, also known as face-centered cubic (FCC), there are 4 atoms per unit cell. 2. **Identify the Formula for Packing Efficiency**: - The packing efficiency (PE) can be calculated using the formula: \[ \text{Packing Efficiency} = \frac{Z \times \frac{4}{3} \pi r^3}{a^3} \times 100 \] where: - \( Z \) = number of atoms per unit cell (for CCP, \( Z = 4 \)) - \( r \) = radius of the sphere - \( a \) = edge length of the unit cell 3. **Determine the Edge Length**: - The edge length \( a \) of the unit cell in a CCP structure is related to the radius \( r \) of the spheres: \[ a = \frac{4r}{\sqrt{2}} = 2\sqrt{2}r \] 4. **Substitute Values into the Formula**: - Substitute \( Z = 4 \) and \( a = 2\sqrt{2}r \) into the packing efficiency formula: \[ \text{Packing Efficiency} = \frac{4 \times \frac{4}{3} \pi r^3}{(2\sqrt{2}r)^3} \times 100 \] 5. **Calculate the Volume of the Unit Cell**: - Calculate \( (2\sqrt{2}r)^3 \): \[ (2\sqrt{2}r)^3 = 8 \times 2\sqrt{2}^3 \times r^3 = 16\sqrt{2}r^3 \] 6. **Plug in the Values**: - Now plug this back into the packing efficiency formula: \[ \text{Packing Efficiency} = \frac{4 \times \frac{4}{3} \pi r^3}{16\sqrt{2}r^3} \times 100 \] 7. **Simplify the Expression**: - The \( r^3 \) cancels out: \[ \text{Packing Efficiency} = \frac{4 \times \frac{4}{3} \pi}{16\sqrt{2}} \times 100 \] 8. **Calculate the Numerical Value**: - Simplifying further: \[ \text{Packing Efficiency} = \frac{\frac{16\pi}{3}}{16\sqrt{2}} \times 100 = \frac{\pi}{3\sqrt{2}} \times 100 \] - Approximating \( \pi \approx 3.14 \): \[ \text{Packing Efficiency} \approx \frac{3.14}{3 \times 1.414} \times 100 \approx 74% \] ### Final Answer: The volume occupied for a cubic close packed lattice of spheres is approximately **74%**. ---

To find the volume occupied for a cubic close packed (CCP) lattice of spheres, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Structure**: - In a cubic close packed (CCP) lattice, also known as face-centered cubic (FCC), there are 4 atoms per unit cell. 2. **Identify the Formula for Packing Efficiency**: ...
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