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The radius of a divaent cation A^(2+) is...

The radius of a divaent cation `A^(2+)` is 94pm and of divalent anion `B^(2-)` is 146pm. The compound AB has:

A

rock salt structure

B

zinc blende structure

C

antifluorite structure

D

cesium chloride like structure

Text Solution

Verified by Experts

The correct Answer is:
A
`(r^(+))/(r^(-))=94/146=0.644`
Thus, `0.414le(r^(+))/(r^(-))lt 0.732`
`therefore` The ionic solid is expected to have NaCl type (rock salt type) structure.
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