The C.N.of `A^(2+)` in `AB_(2)` is 8, then C.N. of B is

Options

A. 8
B. 6
C. 4
D. 2

Explanation

To solve the problem, we need to determine the coordination number (C.N.) of ion B in the compound AB₂, given that the coordination number of A²⁺ is 8.

### Step-by-Step Solution:

1. **Understanding Coordination Number**:
- The coordination number (C.N.) refers to the number of nearest neighboring atoms or ions surrounding a central atom or ion in a complex or crystal structure.

2. **Identify the Given Information**:
- We have the compound AB₂, where A is a cation (A²⁺) and B is an anion (B⁻).
- The coordination number of A²⁺ is given as 8.

3. **Relate the Coordination Numbers**:
- In a compound AB₂, the coordination number of the cation (A) can be related to the coordination number of the anion (B) using the formula:
\[ \text{C.N. of B} = \frac{1}{2} \times \text{C.N. of A} \]

4. **Substituting the Values**:
- Given that the C.N. of A is 8, we can substitute this value into the equation:
\[ \text{C.N. of B} = \frac{1}{2} \times 8 = 4 \]

5. **Conclusion**:
- Therefore, the coordination number of B is 4.

### Final Answer:
The coordination number of B in the compound AB₂ is **4**.

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