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How many unit cells are present in a cub...

How many unit cells are present in a cubic shaped ideal crystal of NaCl of mass `1.0` g ?

A

`1.28times10^(21)`

B

`1.71times10^(21)`

C

`5.14times10^(21)`

D

`2.57times10^(21)`

Text Solution

Verified by Experts

The correct Answer is:
D
Mass of one unit cell (m)=`"Volume "times "density"`
=`a^(3)timesd=a^(3)times(MZ)/(N_(0)a^(3))=(MZ)/(N_(0))`
`therefore m=(58.5times4)/(6.02times10^(23))g`
Number of unit cells in `1 g=1/m`
`=(6.02times10^(23))/(58.4times4)=2.57times10^(21)`
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