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Experimentally it was found that a metal...

Experimentally it was found that a metal oxide has formula `M_(0.98)O`. Metal `M` is present as `M^(2+)` and `M^(3+)` in its oxide ,Fraction of the metal which exists as `M^(3+)` would be

A

`5.08%`

B

`7.01%`

C

`4.08%`

D

`6.05%`

Text Solution

Verified by Experts

The correct Answer is:
C
The formula `M_(0.98)O` shows that if there were 100 O atoms present as `O^(2-)`ions, than 98 M atoms will be present as `M^(2+) and M^(3+)`. Suppose `M^(3+)`= x then `M^(2+)`=98-x. As the compound as a whole is neutral , the total charge on `M^(3+) and M^(2+)` = total charge on 100 `O^(2-) ion`
`x(+3)times(98-x)times2=(100)times2`
`3x+196-2x=200therefore x=2`
`therefore % "of "M^(3+)=4/98times100=4.08%`
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