Home
Class 11
CHEMISTRY
The ratio of close packed atoms to tetra...

The ratio of close packed atoms to tetrahedral holes in cubic close packing is

A

NaCl

B

ZnS

C

`Na_(2) O`

D

CaF_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
In `ZnS, S^(2-)` ions form fcc (or ccp) lattice in which `Zn^(2+)` (cations) occupy alternate tetrahedral voids.
Promotional Banner

Similar Questions

Explore conceptually related problems

The ratio of closed packed atoms to tetrahedral holes in cubic close packing is :

The maximum ra dius of sphere that can be fitted in the octahedral hole of cubical closed packing of sphere of raius r is

Assertion: Hexagonal close packing in more light than cubic close packing. Reason: Hexagonal close packing has C.N of 12 whereas cubic close packing has C.N. of 8.

If the radius of a tetrahedral void is 'r' and radius of atom in close packing is 'R', derive the relation between r and R.

The number of nearest neighbours of each atom in cubic close packing (ccp) and body-centred cubic arrangement (bcc) is respectively

In the cubic close packing, the unit cell has

The number of octahedral sites in a cubical close pack array of N spheres is

What is the co-ordination number of each sphere in cubic close packing and hexagonal close packing ?

In a close packed array of N spheres, the number of tetrahedral holes are

In a hexagonal close packed (hcp) structure of spheres, the fraction of the volume occupied by the sphere is A. In a cubic close packed structure the fraction is B. The relation for A and B is: