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CsBr crystallise in a body centred cubic...

`CsBr` crystallise in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being `6.02xx1023 mol^(-1)`, the density of `CsBr` is

A

`8.25g//cm^(3)`

B

`4.25g//cm^(3)`

C

`0.425g//cm^(3)`

D

`42.5g//cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B

`d=(ZtimesM)/(a^(3)timesN_(A)times10^(-30))`
=`(1times(133+80))/((436.61)^(3)times(6.02times20^(23))times10^(-30))`
`4.25 g //cm^(3)`
(CsBr contains, one formula unit per unit cell)
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