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A student observed four plants (a, b, ...

A student observed four plants (a, b, c, d,). The number of stamens in a equal to those of b. Flower c has ten stamens in but its bundle possesses three times the stamens of inner whorl of a. In d the number of stamens is equal to those present in inner whorl of b. Identify the flower.
(1) Brassica,Tephrosia, Allium, Ocimum
(2) Tephrosia, Ocimum,Brassica, Allium
(3) Taphrosia, Allium, Ocimum, Brassica
(4) Allium, Brassica, Tephrosia, Ocimum

A

Brassica,Tephrosia, Allium, Ocimum

B

Tephrosia, Ocimum,Brassica, Allium

C

Taphrosia, Allium, Ocimum, Brassica

D

Allium, Brassica, Tephrosia, Ocimum.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the information given about the four plants (A, B, C, D) and their stamens. Let's break it down step by step: ### Step 1: Analyze the Information - The number of stamens in plant A is equal to the number of stamens in plant B. - Plant C has 10 stamens, and its bundle possesses three times the number of stamens in the inner whorl of plant A. - Plant D has the same number of stamens as the inner whorl of plant B. ### Step 2: Identify the Number of Stamens 1. **For Plant A and B**: Since A = B, we need to find flowers that have the same number of stamens. - Allium has 6 stamens. - Brassica also has 6 stamens. - Therefore, we can assign A = Allium and B = Brassica. 2. **For Plant C**: It has 10 stamens. The inner whorl of A (Allium) has 6 stamens, so: - The bundle of C must have 3 times the inner whorl of A, which is 3 * 6 = 18 stamens. - However, since C has 10 stamens, this means that the 10 stamens are part of the 18, which confirms that C is Tephrosia (which has a unique arrangement of stamens). 3. **For Plant D**: The number of stamens in D is equal to the inner whorl of B (Brassica), which has 6 stamens. - Therefore, D must be Ocimum, which has 4 stamens (2 long and 2 short). ### Step 3: Final Identification - A = Allium (6 stamens) - B = Brassica (6 stamens) - C = Tephrosia (10 stamens) - D = Ocimum (4 stamens) ### Conclusion Based on the analysis, the correct identification of the flowers is: - A = Allium - B = Brassica - C = Tephrosia - D = Ocimum Thus, the correct option is (4) Allium, Brassica, Tephrosia, Ocimum. ---
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