Match the lists and find the correct option
`{:(,I,,II,),(a.,G_(2)" phase",i.,"Fusion microtubules to form spindle apparatus",),(b.,"Prometaphase",ii.,"Production of energy required for spindle formation",),(c.,"Anaphase",iii.,"Recombination of genetic material",),(d.,"Pachytene",iv.,"Contraction of tublin proteins",),(,,v.,"Reappearance of plasmasome",):}`

Options

A. a-v, b-iv, c-ii, d-iii
B. a-ii, b-iv, c-i, d-v
C. a-v, b-i, c-iv, d-ii
D. a-ii, b-i, c-iv, d-iii

Answer

To solve the problem of matching the two lists, we will analyze each item in Column I and find the corresponding item in Column II.

### Step-by-Step Solution:

1. **Identify G2 Phase**:
- The G2 phase is the stage in the cell cycle where the cell prepares for mitosis. It is responsible for checking the DNA for errors and producing energy needed for spindle formation.
- **Match**: G2 phase → Production of energy required for spindle formation (Option ii).

2. **Identify Prometaphase**:
- During the prometaphase, spindle fibers are formed from microtubule proteins. This is the phase where the spindle apparatus is being assembled.
- **Match**: Prometaphase → Fusion of microtubules to form spindle apparatus (Option i).

3. **Identify Anaphase**:
- Anaphase is characterized by the contraction of tubulin proteins, which pull the chromatids apart towards opposite poles of the cell.
- **Match**: Anaphase → Contraction of tubulin proteins (Option iv).

4. **Identify Pachytene**:
- Pachytene is a stage in meiosis where recombination or crossing over occurs between homologous chromosomes, leading to genetic variation.
- **Match**: Pachytene → Recombination of genetic material (Option iii).

### Final Matches:
- A (G2 phase) → ii (Production of energy required for spindle formation)
- B (Prometaphase) → i (Fusion of microtubules to form spindle apparatus)
- C (Anaphase) → iv (Contraction of tubulin proteins)
- D (Pachytene) → iii (Recombination of genetic material)

### Conclusion:
The correct option that matches all items is **Option 4**:
- A → ii
- B → i
- C → iv
- D → iii