Melting point of arachidonic acid is

Options

A. `13.4^(@)C`
B. `-5^(@)C`
C. `-11^(@)C`
D. `-49*5^(@)C`

Answer

**Step-by-Step Solution:**

1. **Identify Arachidonic Acid**: Arachidonic acid is a polyunsaturated fatty acid that is essential for the human body. It consists of 20 carbon atoms and contains four double bonds.

2. **Understand the Structure**: The double bonds in arachidonic acid are located at the 5th, 8th, 11th, and 14th carbon atoms. This structure contributes to its properties, including its melting point.

3. **Determine the Melting Point**: The melting point of arachidonic acid is reported to be approximately -49.5 degrees Celsius. This means it is a liquid at room temperature.

4. **Evaluate the Options**: The question provides four options for the melting point:
- 13.4 °C
- -5 °C
- -11 °C
- -49.5 °C

5. **Match with Known Data**:
- The melting point of 13.4 °C is incorrect as it does not correspond to arachidonic acid.
- The melting point of -5 °C is associated with linoleic acid, not arachidonic acid.
- The melting point of -11 °C is also incorrect as it pertains to another fatty acid.
- The melting point of -49.5 °C matches the known melting point of arachidonic acid.

6. **Conclusion**: Therefore, the correct answer is that the melting point of arachidonic acid is **-49.5 degrees Celsius**.

---