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In glycolysis, glucose splits into compo...

In glycolysis, glucose splits into compounds which are

A

5-C

B

4-C

C

5-C

D

3-C

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The correct Answer is:
### Step-by-Step Solution: 1. **Understanding Glycolysis**: Glycolysis is the metabolic pathway that converts glucose (a six-carbon sugar) into pyruvate, which is a three-carbon compound. This process occurs in the cytoplasm of the cell and is the first step in both aerobic and anaerobic respiration. 2. **Initial Breakdown of Glucose**: The glycolysis process begins with the phosphorylation of glucose to form glucose-6-phosphate. This reaction is catalyzed by the enzyme hexokinase and requires ATP. 3. **Conversion to Fructose**: Glucose-6-phosphate is then converted into fructose-6-phosphate. This isomerization is facilitated by the enzyme phosphoglucose isomerase. 4. **Formation of Fructose 1,6-bisphosphate**: Fructose-6-phosphate is further phosphorylated to form fructose-1,6-bisphosphate, which is catalyzed by phosphofructokinase, another key regulatory step in glycolysis. 5. **Splitting into Three-Carbon Compounds**: The fructose-1,6-bisphosphate is then split into two three-carbon molecules: glyceraldehyde-3-phosphate (G3P) and dihydroxyacetone phosphate (DHAP). Both of these compounds contain three carbon atoms. 6. **Final Products of Glycolysis**: The end products of glycolysis are two molecules of pyruvate (each containing three carbon atoms) from one molecule of glucose. Therefore, the compounds formed from the splitting of glucose during glycolysis are three-carbon compounds. ### Conclusion: In glycolysis, glucose splits into three-carbon compounds.
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