In aerobic respiration one glucose produces

Options

A. `8 NADH+2FADH_(2)+2ATP`
B. `12 NADH+2FADH_(2)+38ATP`
C. `12 NADH+30 ATP +H_(2)o`
D. `10 NADH+2FADH_(2)+2ATP+2GTP.`

Answer

To solve the question regarding the products of one glucose molecule during aerobic respiration, we can break down the process step by step:

### Step-by-Step Solution:

1. **Glycolysis**:
- Glycolysis is the first step of aerobic respiration and occurs in the cytoplasm.
- One molecule of glucose (C6H12O6) is broken down into two molecules of pyruvate.
- During glycolysis, a net gain of **2 ATP** and **2 NADH** is produced.

2. **Decarboxylation**:
- The pyruvate molecules produced from glycolysis are transported into the mitochondria.
- Each pyruvate undergoes decarboxylation to form acetyl coenzyme A (acetyl CoA).
- This process produces **2 NADH** (1 NADH per pyruvate, and since there are 2 pyruvate molecules, it totals to 2 NADH).

3. **Krebs Cycle (Citric Acid Cycle)**:
- Acetyl CoA enters the Krebs cycle, which occurs in the mitochondrial matrix.
- Each turn of the Krebs cycle produces:
- **3 NADH**
- **1 FADH2**
- **1 ATP (or GTP)**
- Since each glucose molecule produces 2 acetyl CoA, the cycle turns twice, resulting in:
- **6 NADH** (3 NADH x 2)
- **2 FADH2** (1 FADH2 x 2)
- **2 ATP (or GTP)** (1 ATP x 2)

4. **Total Products**:
- Now, we can sum up all the products from each step:
- From Glycolysis: **2 NADH + 2 ATP**
- From Decarboxylation: **2 NADH**
- From Krebs Cycle: **6 NADH + 2 FADH2 + 2 ATP**
- Adding these together:
- Total NADH = 2 (from glycolysis) + 2 (from decarboxylation) + 6 (from Krebs) = **10 NADH**
- Total FADH2 = **2 FADH2** (from Krebs)
- Total ATP = 2 (from glycolysis) + 2 (from Krebs) = **4 ATP**

5. **Final Count**:
- Therefore, the complete breakdown of one glucose molecule in aerobic respiration yields:
- **10 NADH**
- **2 FADH2**
- **4 ATP (or GTP)**

### Final Answer:
In aerobic respiration, one glucose produces **10 NADH, 2 FADH2, and 4 ATP**.