In alcoholic fermentation, two molecules of glucose produce ethanol and `CO_(2)` respectively

Options

A. 2+2
B. 3+3
C. 4+4
D. 6+6

Answer

### Step-by-Step Text Solution:

1. **Understanding the Process of Alcoholic Fermentation**:
- Alcoholic fermentation is an anaerobic process where glucose is converted into ethanol and carbon dioxide. This process occurs in yeast and some bacteria.

2. **Starting with Glucose**:
- The question states that we begin with **two molecules of glucose**.

3. **Conversion of Glucose to Pyruvic Acid**:
- Each molecule of glucose (C₆H₁₂O₆) is broken down through glycolysis to produce **two molecules of pyruvic acid** (C₃H₄O₃).
- Therefore, from **two molecules of glucose**, we will produce:
\[ 2 \text{ glucose} \rightarrow 4 \text{ pyruvic acid} \]

4. **Conversion of Pyruvic Acid to Ethanol and Carbon Dioxide**:
- Each molecule of pyruvic acid is then converted into **one molecule of ethanol** (C₂H₅OH) and **one molecule of carbon dioxide** (CO₂) during fermentation.
- Thus, from **four molecules of pyruvic acid**, we will produce:
\[ 4 \text{ pyruvic acid} \rightarrow 4 \text{ ethanol} + 4 \text{ carbon dioxide} \]

5. **Final Result**:
- Therefore, from **two molecules of glucose**, we ultimately produce:
- **4 molecules of ethanol**
- **4 molecules of carbon dioxide**
- The answer to the question is **4 plus 4**.

6. **Selecting the Correct Option**:
- Based on the options provided:
- 2 + 2 (Incorrect)
- 3 + 3 (Incorrect)
- 4 + 4 (Correct)
- 6 + 6 (Incorrect)
- The correct answer is **4 plus 4**.