A yellow seeded true breeding Pea plant is crossed with green seeded true breeding plant. `F_(1)` plants were yellow seeded showing that allele for yellow colour is

Options

A. Heterozygous
B. Dominant
C. Lethal
D. Epistatic

Answer

To solve the question, we need to analyze the genetic cross between a yellow-seeded true breeding pea plant and a green-seeded true breeding plant.

### Step-by-Step Solution:

1. **Identify the Genotypes of the Parent Plants**:
- The yellow-seeded true breeding plant has the genotype **YY** (homozygous dominant).
- The green-seeded true breeding plant has the genotype **yy** (homozygous recessive).

2. **Perform the Cross**:
- When we cross the yellow-seeded plant (YY) with the green-seeded plant (yy), we can set up a Punnett square to visualize the offspring.
- The gametes from the yellow plant (YY) can only contribute **Y** alleles, while the gametes from the green plant (yy) can only contribute **y** alleles.

3. **Determine the F1 Generation**:
- The F1 generation will consist of all offspring with the genotype **Yy**.
- Since all F1 plants have at least one dominant allele (Y), they will express the dominant phenotype.

4. **Phenotype of the F1 Generation**:
- The phenotype of the F1 generation (Yy) will be yellow seeds because the yellow seed color is dominant over the green seed color.

5. **Conclusion**:
- Since the F1 plants are yellow-seeded, we conclude that the allele for yellow color is **dominant**.

### Final Answer:
The allele for yellow color is **dominant**.

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