A cross between pure tall Pea plant with green pods and dwarf Pea Plant with yellow pods will produce short `F_(2)` plant out of 16

Options

A. 12
B. 13
C. 4
D. 7

Answer

To solve the problem, we need to analyze the genetic cross between the two pea plants and determine the expected phenotypic ratio in the F2 generation. Here's a step-by-step breakdown of the solution:

### Step 1: Identify the parental genotypes
- The pure tall pea plant with green pods can be represented as **TTGG** (homozygous dominant for both traits).
- The dwarf pea plant with yellow pods can be represented as **ttgg** (homozygous recessive for both traits).

### Step 2: Perform the F1 generation cross
- When we cross **TTGG** with **ttgg**, all offspring in the F1 generation will be heterozygous for both traits: **TtGg**.
- This means all F1 plants will be tall with green pods since tall (T) and green (G) are dominant traits.

### Step 3: Self-cross the F1 generation to produce the F2 generation
- The F1 plants (TtGg) will be self-crossed:
- TtGg x TtGg

### Step 4: Use a Punnett square to determine the F2 generation ratios
- For the traits of height (T/t) and pod color (G/g), we can set up a 16-square Punnett square.
- The phenotypic ratio from this cross will be:
- Tall green (TG): 9
- Tall yellow (Tg): 3
- Dwarf green (tG): 3
- Dwarf yellow (tg): 1

### Step 5: Calculate the total number of plants
- In total, there are 16 plants in the F2 generation.
- According to the phenotypic ratio:
- Tall green = 9
- Tall yellow = 3
- Dwarf green = 3
- Dwarf yellow = 1

### Step 6: Identify the number of short (dwarf) plants
- The total number of dwarf plants (short) in the F2 generation is:
- Dwarf green (3) + Dwarf yellow (1) = 4 dwarf plants.

### Conclusion
- Out of 16 plants in the F2 generation, there are 4 short (dwarf) plants.

### Final Answer
- The number of short (dwarf) plants out of 16 in the F2 generation is **4**.

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