Home
Class 12
BIOLOGY
Cross between homozygous black rough (BB...

Cross between homozygous black rough (BBRR) guinea pig and homozygous white smooth guinea pig (bbrr) produced black and rough animals in `F_(1)` generation. Presuming the genes to be present on different chromosomes, the percentage of `F_(2)` individuals which are heterozygous for both the gene pairs would be

A

0.25

B

0.35

C

0.5

D

0.75

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Identify the Parent Genotypes The problem states that we have two homozygous guinea pigs: - One is homozygous black rough (BBRR). - The other is homozygous white smooth (bbrr). ### Step 2: Determine the F1 Generation When these two guinea pigs are crossed, the F1 generation will be heterozygous for both traits: - All F1 offspring will have the genotype BbRr, which means they will be black and rough. ### Step 3: Set Up the F2 Generation To find the F2 generation, we need to self-cross the F1 individuals (BbRr x BbRr). ### Step 4: Use a Punnett Square We can use a Punnett square to determine the genotypes of the F2 generation. Since we are dealing with two traits, we will create a 4x4 Punnett square: | | BR | Br | bR | br | |-----|----|----|----|----| | **BR** | BBRR | BBRr | BbRR | BbRr | | **Br** | BBRr | BBrr | BbRr | BbrR | | **bR** | BbRR | BbRr | bbRR | bbRr | | **br** | BbRr | BbrR | bbRr | bbrr | ### Step 5: Count the Heterozygous Individuals From the Punnett square, we can identify the genotypes: - The heterozygous individuals for both traits (BbRr) appear in the following combinations: - BbRr (occurs 4 times) ### Step 6: Calculate the Total Number of Offspring In total, there are 16 possible combinations (4 rows x 4 columns). ### Step 7: Calculate the Percentage of Heterozygous Individuals To find the percentage of F2 individuals that are heterozygous for both gene pairs (BbRr): - There are 4 BbRr out of 16 total offspring. - Therefore, the percentage is (4/16) * 100 = 25%. ### Conclusion The percentage of F2 individuals that are heterozygous for both gene pairs is **25%** or **0.25**. ---
Promotional Banner

Topper's Solved these Questions

  • GENETIC BASIS OF INHERITANCE

    DINESH PUBLICATION ENGLISH|Exercise Check your Grasp|30 Videos
  • GENETIC BASIS OF INHERITANCE

    DINESH PUBLICATION ENGLISH|Exercise Check your Grasp|30 Videos
  • FRUIT AND SEED DISPERSAL

    DINESH PUBLICATION ENGLISH|Exercise CHECK YOUR GRASP|10 Videos
  • GROWTH, REPAIR, REGENERATION AND AGEING

    DINESH PUBLICATION ENGLISH|Exercise Brain Teasers-VI[B]|6 Videos

Similar Questions

Explore conceptually related problems

Find out the F_(2) phenotypic ratio, when a mulatto individual is cross ed to its homozygous dominant individual. (Given that skin colour is controlled by three gene pairs )

In a monohybrid cross between two heterozygous individuals, percentage of pure homozygous individuals obtained in F_(1) generation will be

A trihybrid cross involve three pair of characters which will give rise to the "F"_(1) hybrids which are heterozygous for three genes. How many types of gametes will be produced in both male and female?

In rabbit black skin (B) is dominant over brown skin (b) and short hair (S) is dominant over long hair (s). If homozygous black-short haired male is ceossed with a homozygous brown-long haired female. All F_(1)- offspring are heterozygous black-short haired. F_(1) male crossed with F_(1) female. In F_(2) generation what is the percentage of homozyhous black-short haired offspring :-

When a yellow mouse were crossed to another yellow mouse, the F_(1) generation produces yellow and brown-black mice in the ration 2:1. The yellow mice are never homozygous. The reason is

When a red grain variety of wheat is crossed with another white grain vartiety F_(1) hybrid is produced. On selfing of this F_(1)- hybrid, how many offsprings of F_(2)- generation resemble phenotypically to it's parents (let grain colour of wheat controlled by three gene pairs )

A snapdragon plant homozygous for red flower when crossed with a white flowered plant of the same species produced pink flowers in F_(1) generation. (a) What is the phenotypic expression called ? (b) Work out the cross to show the F_(2) generation when F_(1) was self-pollinated. Give the phenotypic and genotypic ratios of f_(2) generation. (c) How do you compare the f_(2) phenotypic and genotypic ratios with those of Mendelian monohybrid f_(2) ?

A snapdragon plant homozygous for red flower when crossed with a white flowered plant of the same species produced pink flowers in F_(1) generation. (a) What is the phenotypic expression called ? (b) Work out the cross to show the F_(2) generation when F_(1) was self-pollinated. Give the phenotypic and genotypic ratios of f_(2) generation. (c) How do you compare the f_(2) phenotypic and genotypic ratios with those of Mendelian monohybrid f_(2) ?

(a) Dihybrid cross between two garden pea plant one homozygous tall with round seeds and the other with wrinkled seeds was carried. (i) Write the genotype and phenotype of the F_(1) progeny obtained from this cross. (ii) Give the different types of gametes of the F_(1) progeny. (iii) Write the phenotypes and its ratios of the F_(2) generation obtained in this cross along with the explanation provided by Mendel. (b) How were the observations of F_(2) progeny of dihybrid crosses in Philosophical by Morgan different from that of Mendel carried in Pea plants ? Explain giving reasons.

In guinea pig, black short hair (BBSS) is dominant over white long hair (bbss). In the dihybrid cross, F_(2) genotype BBSS, BbSS,BBSs and BbSs appears in the ratio of

DINESH PUBLICATION ENGLISH-GENETIC BASIS OF INHERITANCE-Revision Questions From Competitive Exams
  1. The ratio of 9:3:3:1 is due to

    Text Solution

    |

  2. Find out the incorrect statement. (a) There are several pairs of const...

    Text Solution

    |

  3. Cross between homozygous black rough (BBRR) guinea pig and homozygous ...

    Text Solution

    |

  4. Phenotype of an organism is the result of

    Text Solution

    |

  5. In Mendel's experiments with garden pea, round seed shape (RR) was dom...

    Text Solution

    |

  6. Test cross involves

    Text Solution

    |

  7. Two pea plants were subjected cross pollination. Of the 183 plants pro...

    Text Solution

    |

  8. Which pair of features represents polygenic inheritance ? (a) Human ey...

    Text Solution

    |

  9. Matting of an organism to a double recessive in order to determine whe...

    Text Solution

    |

  10. Human skin colour is polygenic trait with each dominant determing a pa...

    Text Solution

    |

  11. Test cross is performed to know the genotype. It is cross between

    Text Solution

    |

  12. Possible blood groups of children born to parents having A and AB gr...

    Text Solution

    |

  13. When pure long plant having white flower is crossed with pure dwarf pl...

    Text Solution

    |

  14. Which of the following is correct for dihybrid cross ?

    Text Solution

    |

  15. Word genetics comes from

    Text Solution

    |

  16. Selfing of hybrid yellow round seeded (YyRr) Pea plants, the phnotypes...

    Text Solution

    |

  17. The gene for right handedness is dominant over the gene for left hande...

    Text Solution

    |

  18. Match the genetics phenomena with their respective ratios

    Text Solution

    |

  19. In a monohybrid cross, the genotypic ratio of "F"(2) is:

    Text Solution

    |

  20. In humans blue eye colour is recessive to brown eye colour. If a boy h...

    Text Solution

    |