A cross between two heterozygous individuals will yield homozygous individuals

Options

A. 2
B. 4
C. 6
D. 8

Answer

To solve the question about the cross between two heterozygous individuals and the resulting homozygous individuals, we can follow these steps:

### Step-by-Step Solution:

1. **Define the Genotypes**:
- Let's denote the alleles for a trait (e.g., height in pea plants) as T (dominant) and t (recessive).
- Since we are crossing two heterozygous individuals, their genotypes will be Tt (where T is dominant and t is recessive).

2. **Set Up the Punnett Square**:
- Create a Punnett square to visualize the cross between the two Tt individuals.
- The rows and columns will represent the gametes from each parent:
```
T t
__________
T | TT | Tt |
|______|______|
t | Tt | tt |
|______|______|
```

3. **Identify the Genotypic Outcomes**:
- From the Punnett square, we can see the possible genotypes of the offspring:
- TT (homozygous dominant)
- Tt (heterozygous)
- Tt (heterozygous)
- tt (homozygous recessive)

4. **Count the Homozygous Individuals**:
- In the outcomes, we have:
- 1 TT (homozygous dominant)
- 2 Tt (heterozygous)
- 1 tt (homozygous recessive)
- Therefore, the total number of homozygous individuals (TT and tt) is 2 (1 TT + 1 tt).

5. **Calculate the Proportions**:
- Out of the 4 total offspring, 2 are homozygous (1 TT and 1 tt), which gives us a ratio of 2 homozygous individuals out of 4 total individuals.

6. **Conclusion**:
- Thus, when two heterozygous individuals are crossed, the number of homozygous individuals produced is 2.

### Final Answer:
The number of homozygous individuals produced from the cross of two heterozygous individuals is **2**.

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