Total number of types of gametes produced in a cross between a negro and albino parents is

Options

A. 2
B. 16
C. `08`
D. `04`

Answer

To determine the total number of types of gametes produced in a cross between a Negro parent (homozygous dominant) and an albino parent (homozygous recessive), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotypes of the Parents**:
- The Negro parent is homozygous dominant for the traits, which can be represented as **AABBCC**.
- The albino parent is homozygous recessive for the traits, represented as **aabbcc**.

2. **Determine the Types of Gametes Produced by Each Parent**:
- The Negro parent (AABBCC) can only produce one type of gamete because it is homozygous for all traits. The gamete produced will be **ABC**.
- The albino parent (aabbcc) can also only produce one type of gamete, which will be **abc**.

3. **Calculate the Total Number of Types of Gametes**:
- Since each parent produces only one type of gamete, the total number of types of gametes from the cross will be:
- From the Negro parent: 1 (ABC)
- From the albino parent: 1 (abc)
- Therefore, the total number of different types of gametes produced in this cross is **1 x 1 = 1**.

4. **Conclusion**:
- The total number of types of gametes produced in a cross between a Negro and an albino parent is **2** (one from each parent).

### Final Answer:
The total number of types of gametes produced in a cross between a Negro and an albino parent is **2**.

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