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When Cl(2) is passed through hot NaOH , ...

When `Cl_(2)` is passed through hot NaOH , oxidation number of Cl changes from

A

0 to -1

B

0 to +1

C

0 to -2

D

0 to +2

Text Solution

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The correct Answer is:
A, B
`Cl_(2)+2NaOHrarrNaCl+NaOCl+H_(2)O`
O.N of Cl changes from O in `Cl_(2)` in -1 to NaCl and +1 and NaOCl.
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