Home
Class 12
CHEMISTRY
Assertion :- Zn(s)+Cu^(+2)(aq)rarr Zn^(+...

Assertion :- `Zn(s)+Cu^(+2)(aq)rarr Zn^(+2)(aq)+Cu(s)` can be spilt into following half reactions
`{:(Zn(s)rarrZn^(+2)+2e^(-),),(,"(Oxidation half reaction)"),(Cu^(+2)(aq)+2e^(-)rarrCu,),(,"(Reduction half reaction)"):}`
Reason : Every redox reaction can be spilt into two reactions, one representing loss of electrons and the other representing gain of electrons.

A

Both A and R are true and R is the correct explanation of A

B

Both A and R are true but R is not a correct explanation A

C

A is true but R is false

D

A is false but R is true

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Zn(s) + Cu^(2+)(aq) rarr Zn^(2+)(aq) + Cu(s) The cell representation for the above redox reaction is

The cell reaction Zn(s) + Cu^(+2)rarr Zn^(+2) + Cu(s) is best represented as :

Divide the following redox reactions into oxidation and reduction half reactions. Zn + Cu^(2+) to Zn&(2+) + Cu

STATEMENT-1: In the reaction Zn(s) + Cu^(2+)(aq) to Zn^(2+)(aq) + Cu(s) . Cu^(2+) ions act as oxidising agent and Zn atoms act as a reducing agent. STATEMENT-2: Every redox reaction cannot be splitted into two reactions one being oxidation and the other being reductioin. STATEMENT-3: The oxidation numbers are artifical and are useful as a book keeping device of electrons in reactions.

Split the following redox reactions into two half reactions : Zn+Fe^(2+)toZn^(2+)+Fe

Divide the following redox reactions into oxidation and reduction half reactions. Zn + Pb^(2+) to Zn^(2+) + Pb

E.M.F. of Ni(s) | Ni^(2+) (aq)||Cu^(2+) (aq)| Cu(s) cell can be increased by

Cu^(2+)(aq.) does not undergo redox reaction with solution:

Cu^(2+)(aq.) does not undergo redox reaction with solution:

Identify the oxidant and the reductant in the following reactions: a. Zn(s)+(1)/(2)O_(2)(g)rarrZnO(s) b. Zn(s)+2H^(o+)(aq)rarrZn^(2+)(aq)+H_(2)(g)