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In the reaction A^(+x) + MnO(4)^() to AO...

In the reaction `A^(+x) + MnO_(4)^() to AO_(3)^() + Mn^(++) +(1)/(2)O, ` if one mole fo `MnO_(4)^()` oxidises 1.67 moles of `A^(+x) ` to `AO_(3)^()` , then what will be the value of x ?

A

5

B

3

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
`overset(+7)(MnO_(4)^(-))+5e^(-)rarrMn^(2+)`
1 mole of `MnO_(4)^(-)` accepts five moles of electrons
`:. 1.67` moles of `M^(x+)` loose five moles of electrons
`:.` Loss of electrons by 1 mole of
`M^(x+)=(5)/(1.67)~~3`
`overset(+x)(M^(x))rarroverset(+5)(MO_(3)^(-))+n e^(-)`
`x=5-n`
But `x=3`
`:. 3=5-n`
or `n=2`.
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