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The oxidation number of S in Na(2)S(4)O(...

The oxidation number of `S` in `Na_(2)S_(4)O_(6)` is

A

`+2.5`

B

`+2 and +3` (two S have +2 and other two have +3)

C

`+2 and +3` (three S have +2 and one S has +3)

D

`+5 and 0` (two S have +5 and the other two have 0)

Text Solution

Verified by Experts

The correct Answer is:
D
The structural formula of `Na_(2)S_(4)O_(6)` (sodium tetrathionate) is as follows
`{:(" O O"),(" || ||"),(Na^(+)O^(-)-S-S-S-S-O^(-)Na^(+)),(" || ||"),(" O O"):}`
The O.N of the two central sulphur atoms which are linked only to each other i.e., -S-S- is zero. Let the O.N of the other two sulphur atoms be x each. Here, O.N. of O is -2 and O.N. of tetrathionate ion = -2
`:. 6xx(-2)+2xx0+2xx x=-2`
`-12+2x=-2`
`x=5`
Thus, two S atoms in `Na_(2)S_(4)O_(6)` have O.N. of zero each, while the other two S atoms have O.N of 5 each.
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