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Equivalent weight of MnO(4)^(ɵ) in acidi...

Equivalent weight of `MnO_(4)^(ɵ)` in acidic neutral and basic media are in ratio of:

A

`3:5:15`

B

`5:3:1`

C

`5:1:3`

D

`3:5:5`

Text Solution

Verified by Experts

The correct Answer is:
D
`KMnO_(4)` can act as an O.A in acidic, basic and neutral mediums as follows :
In acidic medium,
`MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O`
In basic medium
`MnO_(4)^(-)+2H_(2)O+3Fe^(-)rarrMnO_(2)+4OH^(-)`
In neutral medium
`MnO_(4)^(-)+2H_(2)O+3Fe^(-)rarrMnO_(2)+4OH^(-)`
Let molecular mass of `KMnO_(4)=M`
`:.` Ratio of Eq mass of `KMnO_(4)` in acidic, basic and neutral mediums are `(M)/(5):(M)/(3):(M)/(3)or3:5:5`.
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