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If X is the specific resistance of the s...

If `X` is the specific resistance of the solution and `N` is the normality of the solution, the equivalent conductivity of the solution is given by
(a)`(1000x)/(N)`
(b)`(1000)/(Nx)`
(c)`(1000N)/(x)`
(d)`(Nx)/(1000)`

A

`(1000x)/(N)`

B

`(1000)/(Nx)`

C

`(1000N)/(x)`

D

`(Nx)/(1000)`

Text Solution

Verified by Experts

The correct Answer is:
B
Specific conductance `=(1)/("specific resistance")=(1)/(rho)`
so `^^_(eq)=("sp.conductance"xx1000)/(C("ingeq/L"))=(1000)/(xN)`
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