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For an electrolyte solution of 0.05 mol...

For an electrolyte solution of `0.05 mol L^(-1)` , the conductivity has been found to be `0.0110 S cm^(-1)`. The molar conductivity is

A

`0.055S cm^(2)"mol"^(-1)`

B

`550 S cm^(2) "mol"^(-1)`

C

`0.22 S cm^(2) "mol"^(-1)`

D

`220S cm^(2)"mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`^^m=(0.011xx1000)/(0.05)=220.5cm^(2)"mol"^(-1)`
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