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The values of wedge(m)^(oo) forNH(4)Cl,N...

The values of `wedge_(m)^(oo)` for`NH_(4)Cl,NaOH,` and `NaCl` are, respectively, `149.74,248.1`,and `126.4 ohm^(-1)cm^(2)eq^(-1)`. The value of `wedge_(eq)^(oo)NH_(4)OH` is

A

371.44

B

271.44

C

71.44

D

It cannot be calculated from the data given.

Text Solution

Verified by Experts

The correct Answer is:
B
`^^_(eq)^(oo)(NH_(4)OH)`
`=^^_(eq)^(oo)(NH_(4)Cl)+^^_(eq)^(oo)(NaOH)-^^_(eq)^(oo)(NaCl)`
`=(149.7+248.1-126.4)`
`= 271.44 Omegacm^(2)eq^(-1)`
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