Home
Class 12
CHEMISTRY
For a reaction A(s)+2B^(o+) rarr A^(2+)+...

For a reaction `A(s)+2B^(o+) rarr A^(2+)+2B`
`K_(c)` has been found to be `10^(12)`. The `E^(c-)._(cell)` is

A

0.354V

B

0.708V

C

0 .0098V

D

1.36V

Text Solution

Verified by Experts

The correct Answer is:
A

`DeltaG=-RT` in `k_(c)`
Promotional Banner

Similar Questions

Explore conceptually related problems

For a reaction A(s) + 2B^(+) rarr A^(2+)+2B(s). K_(c) has been found to be 10^(14) The E^(o) ""_(cell) is :

For a reaction: A(s) + 2B ^(+) rarr A^(2+) +2 B (s). K_(aq) has been found to be 10^(12) The E^(o) cell is :

For the redox reaction Zn(s) + Cu^(2+) (0.1M) rarr Zn^(2+) (1M) + Cu(s) that takes place in a cell, E^(o)""_(cell) is 1.10 volt. E_(cell) for the cell will be:

For a reaction A (s) + B^(2+) rarr B(s) + A ^(2+) , at 25^(@) C E^(o) "" _(cell) = 0.2955 V. Hence, K_(eq) will be :

For the reaction : A+2B^(3+) rarr 2B^(2+)+A^(2+) E^(c-) of the given redox reaction is : A^(2+)+2e^(-) rarr A E^(c-)=Xv B^(3+)+e^(-) rarr B^(2+) E^(c-)=yV

For the reaction : A + 2B rarr C + D , the expression of rate of reaction will be :

For the elementary reaction, A+2B rarr C , the rate law will be equal to :-

What is E^(c)._(red) for the reaction : Cu^(2+)+2e^(-) rarr Cu in the half cell Pt_(S^(2)|CuS|Cu) . if E^(c-)._(Cu^(2+)|Cu) is 0.34V and K_(sp) of CuS=10^(-35) ?

In a Galvanic cell involving the redox reaction: A^(2+)+ B_((s)) Leftrightarrow A_((s))+B^(2+) The E_("cell") will not be equal to E_("cell")^(0) when

Given the equilibrium constant : K_(c) of the reaction : Cu(s) + 2Ag^(+)(aq) rightarrow Cu^(2+) (Aq) + 2Ag(s) is 10xx10^(15) , calculate the E_(cell)^(@) of this reaction at 298K . ([2.303 (RT)/(Ft) at 298K = 0.059V])