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The number of Faradays required to depos...

The number of Faradays required to deposit 1g equivalent of aluminium (At. Wt. 27) from a solution of `AlCl_(3)`

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
A
`Al^(3+)+3e^(-)rarrAl`
For 27g Al electrons needed=3
For `(27)/(3)g Al` elec trons needed
`=(3)/(27)xx(27)/(3)=1` electron
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