1.08 g of an element was displaced when a current of one ampere
was passed through the solution of salt of the element for 16
minutes and five seconds. The equivalent weight of the element is

Options

A. 108
B. 5.4
C. 1.08
D. 10.8

Explanation

To find the equivalent weight of the element, we will use the formula:

\[ E = \frac{W}{Q} \]

where:
- \( E \) is the equivalent weight,
- \( W \) is the weight of the element displaced (1.08 g),
- \( Q \) is the quantity of electricity passed through the solution.

### Step 1: Calculate the Quantity of Electricity (Q)

The quantity of electricity \( Q \) can be calculated using the formula:

\[ Q = I \times T \]

where:
- \( I \) is the current (1 A),
- \( T \) is the time in seconds.

First, we need to convert the time from minutes and seconds to seconds.

Given time is 16 minutes and 5 seconds:

\[ T = 16 \text{ minutes} \times 60 \text{ seconds/minute} + 5 \text{ seconds} = 960 + 5 = 965 \text{ seconds} \]

Now, substituting the values into the formula for \( Q \):

\[ Q = 1 \text{ A} \times 965 \text{ seconds} = 965 \text{ coulombs} \]

### Step 2: Substitute Values into the Equivalent Weight Formula

Now we can substitute \( W \) and \( Q \) into the equivalent weight formula:

\[ E = \frac{W}{Q} = \frac{1.08 \text{ g}}{965 \text{ C}} \]

### Step 3: Calculate the Equivalent Weight

To find the equivalent weight, we can use the relation that involves Faraday's constant (approximately 96500 C/mol):

\[ E = \frac{W \times 96500}{Q} \]

Substituting the values:

\[ E = \frac{1.08 \text{ g} \times 96500 \text{ C/mol}}{965 \text{ C}} = \frac{1.08 \times 96500}{965} \]

Calculating this gives:

\[ E = 1.08 \times 100 = 108 \text{ g/equiv} \]

### Final Answer

The equivalent weight of the element is **108 g/equiv**.

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