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The total number of electrons in 4.2 g o...

The total number of electrons in 4.2 g of `N^(3-)` ion is (`N_(A)` is the Avogadro's number)

A

96500

B

`2.89xx10^(5)`

C

`1.45xx10^(6)`

D

`6xx10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
B
One `N^(3-)` ion has 3 units of electric charge
`therefore` 1 g ion of `N^(3-)` has `3xx6.023xx10^(23)` electrons
or 1 g ion of `N^(3-)` has `3xx6.023xx10^(23)` electrons
or 1 g ion `N^(3-)` has `3xx96500` coulomb charge
`=289500=2.89xx10^(6)C`
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