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Calculate DeltaG(r)^(@) of the following...

Calculate `DeltaG_(r)^(@)` of the following reaction
`Ag^(+)(aq)+cI^(-)(aq)rarrAgCI(s)`
Given
`DeltaG_(r)^(@)(AgCI)rarr-109 kJ Mol^(-1)`
`DeltaG_(r)^(@)(CI^(-))rarr-129 kJ Mol^(-1)`
`DeltaG_(r)^(@)(ag^(-))rarr77 kJ Mol^(-1)`
(i)Represent the above reaction in form of a cel
(ii) Calcualte `E^(@)` of the cel
(iii) Find `log_(10)K_(sp)` of AgCI

A

1.71V

B

1.591V

C

3.182V

D

3.07V

Text Solution

Verified by Experts

The correct Answer is:
b
`DeltaG_("reaction")^(@)=DeltaG_(f)^(@)(ZnO)-DeltaG^(@)(Ag_(2)O)`
`=-3.18.3+11.21`
`=-30.09xx10^(2)J`
`DeltaG^(@)= -nE^(@)F`
`therefore E^(@)=(-DeltaG^(@))/(nF)`
Here n=2
`therefore E^(@)=(+3.07.09xx10^(3))/(2xx96500)=1.591V`
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