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The e.m.f of the following cell Ni(s)/...

The e.m.f of the following cell
`Ni(s)//NiSO_(4)(1.0M) ||H^(+)(1.0M)|H_(2)(1atm), Pt` at `25^(@)C` is `0.236V`. The standard free energy which can be produce is

A

`1.3xx10^(-1)`

B

`8.0xx10^(-2)`

C

`3.0xx10^(-1)`

D

`3.0xx10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
c
The half cell reaction and overall recation are
`Ni rarrNi^(2+)+2e^(-)`
`Cl_(2)+2e^(-)rarr2Cl^(-)`
`NirarrNi^(2+)+2Cl^(-)`
`therefore Q([Ni^(2+)][Cl^(-)](2))/([pCl_(2)])`
`=(0.19xx(0.4)^(4))/(0.1)=0.304`
`=3.04xx10^(-1)`
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