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1L of 1M CuSO(4) solution is electrolyze...

`1L` of `1M CuSO_(4)` solution is electrolyzed using `Pt` cathode and `Cu` anode. After passing `2F` of electricity, the `[Cu^(2+)]` will be

A

`M//3`

B

`M//2`

C

`M//4`

D

0

Text Solution

Verified by Experts

The correct Answer is:
d
`Cu^(2+)+2e^(-) rarrCu`
2F will decompose 1 mol of `Cu^(2+)` and will deposit 1 mol of copper.
1L of 1M `CuSO_(4)` solution contains 1 mol of `CuSO_(4)`
therefore, molarity after electrolysis =0
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