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M^(2+) +2e rarr M. 0.275 g of metal M is...

`M^(2+) +2e rarr M. 0.275 g` of metal `M` is deposited at the cathode due to passage of `1A` of current for `965s.` Hence atomic weight of the metal `M` is:-

A

55

B

27.5

C

13.75

D

110

Text Solution

Verified by Experts

The correct Answer is:
A
Let at, mass of `M=m`
`M^(2+)+ 2e^(-)rarrm`
`2xx96500C mg`
`q=1xxt=1xx965=965C`
`2xx96500C` deposit M=mg
965C will deposit `M=(m)/(200)g`
A.T.Q. `(m)/(200)=0.275`
`m=27.5xx2=55.0g`
`therefore` At. Mass of M=55
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