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The resistance of a 0.1 N solution of ac...

The resistance of a `0.1 N` solution of acetic acid is `250 Omega` when measured in a cell of cell constant `1.15cm^(-1)` . The equivalent conductance `( ` in `ohm^(-2) cm^(2) eq^(-1))` of `0.1 N` acetic acid is

A

4.6

B

9.2

C

18.4

D

0.023

Text Solution

Verified by Experts

The correct Answer is:
A
Conductivity `(k)=(1)/(R)xx`Cell constant
`=(1)/(250)xx1.15`
`^^_(eq)=(kxx1000)/(N)=(1.15)/(250)xx(1000)/(1.0)`
`=4.6 ohm^(-1) cm^(2) eq^(-1)`
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