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On the basis of information available from the reaction
`(4)/(3)Al+O_(2) rarr (2)/(3)Al_(2)O_(3),DeltaG = -827kJ mol^(-1)`, the minimum emf required of `O_(2)` to carry out of the electrolysis of `Al_(2)O_(3)` is `(F=96,500 C mol^(-1))`

A

8.56V

B

2.14V

C

4.28V

D

6.42V

Text Solution

Verified by Experts

The correct Answer is:
B
For the reaction
`(2)/(3)Al_(2)O_(3)rarr(4)/(3)Al+O_(3)`
`DeltaG=872xx10^(3)J "mol"^(-1)`
`(4)/(3)Al^(3+)+4e^(-)rarr(4)/(3)Al`
`therefore` n=4
Here `DeltaG=-nE^(@)F`
`E^(@)=-(DeltaG)/(nF)=(827000J "mol"^(-1))/(4xx96500C "mol"^(-1))`
=-2.14V
Thus minimum e.m.f. required =2.14V
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