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An electric current is passed through a silver voltameter connected to a water voltameter. The cathode of the silver voltameter weighed `0.108`g more at the end of the electrolysis. The volume of oxygen evolved at STP is:

A

`56cm^(3)`

B

`550cm^(3)`

C

`5.6cm^(3)`

D

`11.2cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
C

`("Mass of Ag deposited")/("Mass of" O_(2) "evolved")=("Eq. mass of Ag")/("Eq. mass of" O_(2))`
`(0.108)/(m(O_(2)))=(108)/(8)`
`m(O_(2))=(8xx0.108)/(108)=8xx10^(-3)g`
`32gO_(2)=22400 cm^(3)` at N.T.P.
`therefore 8xx10^(-3)g "of" O_(2)=(22400)/(32)xx8xx10^(-3)cm^(3)`
at N.T.P.
`=5.6cm^(3)` at N.T.P.
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